To print higher-resolution math symbols, click the
Hi-Res Fonts for Printing button on the jsMath control panel.
No jsMath TeX fonts found -- using image fonts instead.
These may be slow and might not print well.
Use the jsMath control panel to get additional information.
jsMath Control PanelHide this Message

jsMath

Den Hartog’s Mechanics

A web-based solutions manual for statics and dynamics

Problem 26

The free-body-diagram for the jeep looks like this:

To get the vertical force on the front axle, we take moments about the rear wheel contact point, B:

\sum M_B = 1500\,\cdot\,2 - 2500\,\cdot\,4 + 8 F_{Ay} = 0

From this equilibrium equation we get F_{Ay} = 875\,\rm{lbs}. To get the vertical force on the rear axle, we use this answer in the vertical force equilibrium equation:

\sum F_x = 875 + F_{By} - 2500 = 0

From this we get F_{By} = 1625\,\rm{lbs}.

Notice that Den Hartog doesn’t ask us to determine the horizontal components of F_A and F_B. Good thing, too, because there isn’t enough information to do so. We can easily figure out that the sum of the two horizontal forces is 1500 lbs, but that’s as far as we can go. Look back at the FBD: there are four unknown forces acting on the jeep. Since we only have three equations of planar statics, the mathematics won’t allow us to get a solution for all four unknowns.

Problem 27Problem 25

Last modified: January 22, 2009 at 8:32 PM.