Superthin table?
December 18, 2008 at 2:58 PM by Dr. Drang
This item at BoingBoing Gadgets caught my eye. It’s about a table constructed of carbon fiber.
The “Surface Table” by John Barnard and Terence Woodgate is threemeters long — and just twomillimeters thick, due to its construction from carbon fiber.
Carbon fiber composites are wonderful materials, but my first impression was that such a table would be way too flexible to be anything but a conversation piece. But since impressions mean very little, let’s do a little structural analysis.
The table is basically a simplysupported beam. The deflection of a simplysupported beam under a concentrated load at its center is
$$\delta =\frac{P{L}^{3}}{48EI}$$where $\delta $ is the deflection, P is the load, E is the modulus of elasticity, and I is the crosssectional moment of inertia. The moment of inertia can be determined through the formula
$$I=\frac{b{h}^{3}}{12}$$where b is the width of the table and h is the thickness. Plugging this into the formula for the deflection, and doing a little algebra, we get
$$\frac{\delta}{P}=\frac{(L/h{)}^{3}}{4Eb}$$The table is said to be 3 meters long and 2 millimeters thick, so $L/h=1500$. Based on the photo, I would judge the width of the table to be about 750 mm.
The modulus of elasticity will depend on the type of carbon fiber used, the arrangement of the fibers, and the matrix into which the fibers are laid. I’m no carbon fiber expert, but it appears from sites like this that the modulus is unlikely to be more than 500 GPa. One gigapascal is $1000\phantom{\rule{0.222em}{0ex}}\mathrm{N}/\mathrm{m}{\mathrm{m}}^{2}$, so we’ll assume $E=500,000\phantom{\rule{0.222em}{0ex}}\mathrm{N}/\mathrm{m}{\mathrm{m}}^{2}$.
So
$$\frac{\delta}{P}=\frac{{1500}^{3}}{4(500,000)(750)}=2.25\phantom{\rule{0.222em}{0ex}}\mathrm{m}\mathrm{m}/\mathrm{N}$$which means that the table, as described, will deflect over 2 mm for every newton^{1} of load placed at its center. That’s way too flexible.
It’s possible that my estimate of the table’s width is low, but increasing the value of the width won’t change the stiffness dramatically because the stiffness varies directly with the width. Big stiffness changes will only come with changes in the thickness; the stiffness varies with the cube of the thickness.
My guess—and there’s a suspicion of this in the BB Gadgets item, too— is that the table is thicker at the center. If we assume a 5 mm thickness over most of the interior of the table, the center will deflect 0.144 mm per newton—stiff enough to carry a few light items without looking like a hammock.
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A newton, for those of you unfamiliar with the unit, is less than a quarter of a pound. It’s defined as the force necessary to accelerate a one kilogram mass at one meter per second squared. ↩